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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Which three are DATETIME data types that can be used when specifying column definitions? (Choose three.)

A) INTERVAL YEAR TO MONTH
B) TIMESTAMP WITH DATABASE TIMEZONE
C) INTERVAL MONTH TO DAY
D) INTERVAL DAY TO SECOND
E) TIMESTAMP

2. What does the FORCE option for creating a view do?

A) creates a view with constraints
B) creates a view even if the underlying parent table has constraints
C) creates a view regardless of whether or not the base tables exist
D) creates a view in another schema even if you don't have privileges

3. You define a multiple-row subquery in the WHERE clause of an SQL query with a comparison operator "=".
What happens when the main query is executed?

A) You cannot define a multiple-row subquery in the WHERE clause of a SQL query.
B) The main query executes with the last value returned by the subquery.
C) The main query fails because the multiple-row subquery cannot be used with the comparison operator.
D) The main query executes with the first value returned by the subquery.
E) The main query executes with all the values returned by the subquery.

4. In a SELECT statement that includes a WHERE clause, where is the GROUP BY clause placed in the SELECT statement?

A) Immediately after the SELECT clause
B) After the WHERE clause
C) Before the FROM clause
D) Before the WHERE clause
E) After the ORDER BY clause

5. Exhibit

Examine the data in the EMPLOYEES and DEPARTMENTS tables.
You want to retrieve all employees' last names, along with their manager's last names and their department names. Which query would you use?

A) SELECT last_name, manager_id, department_name
FROM employees e
JOIN departments d ON (e.department_id = d.department_id) ;
B) SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)
C) SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
D) SELECT e.last_name, m.last_name, department_name
FROM employees e
RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
E) SELECT e.last_name, m.last_name, department_name
FROM employees e
LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id)
RIGT OUTER JOIN departments d ON (e.department_id = d.department_id);
F) SELECT last_name, manager_id, department_name
FROM employees e
FULL OUTER JOIN departments d ON (e.department_id = d.department_id);

Solutions: